The heat-loss method
Heat escapes through each surface by conduction at a rate Q = A × ΔT ÷ R, in Btu/h, where A is the area in ft², ΔT the indoor–outdoor temperature difference in °F, and R the surface's thermal resistance in ft²·°F·h/Btu. Windows are rated with a U-factor instead, Q = U × A × ΔT, where U = 1 ÷ R.
Outdoor air leaking in must also be warmed: Q = 1.08 × CFM × ΔT. The 1.08 comes from standard air, 0.075 lb/ft³ × 0.24 Btu/(lb·°F) × 60 minutes per hour. Leakage in CFM is room volume × air changes per hour ÷ 60.
| Term | Formula (Btu/h) |
|---|---|
| Walls | net wall area × ΔT ÷ R |
| Windows and doors | U × area × ΔT |
| Ceiling | ceiling area × ΔT ÷ R |
| Air leakage | 1.08 × volume × ACH ÷ 60 × ΔT |
Worked example
A 15 × 12 ft corner room with 8 ft ceilings, 27 ft of exterior wall, 30 ft² of windows, R-11 walls, U-0.30 windows, an R-38 attic above and 0.5 air changes per hour, heated to 70 °F when it is 10 °F outside (ΔT = 60 °F).
Walls: (27 × 8 − 30) × 60 ÷ 11 = 1,015. Windows: 0.30 × 30 × 60 = 540. Ceiling: 180 × 60 ÷ 38 = 284. Air: 1,440 × 0.5 ÷ 60 = 12 CFM, × 1.08 × 60 = 778. Total about 2,616 Btu/h, or 0.77 kW.
What it leaves out
This is a steady-state heating estimate. It ignores floor and basement losses, thermal bridging beyond the whole-wall R-value you enter, duct losses, and free heat from sun, people and appliances. It does not estimate air-conditioning loads, which depend heavily on solar gain and humidity.
The default R-values, U-factor and air-change rate are example inputs, not measurements of your home. Replace them with your own figures, and size real heating equipment with a full load calculation such as ACCA Manual J.