Power Factor Calculator

Work out a load's power factor and phase angle, and size the power factor correction capacitors needed to reach a target such as 0.95.

Power factor0.8000
kW

1e-9 – 1000000000000

kVA

1e-9 – 1000000000000

0.01 – 1

V (line-to-line for three-phase)

1e-9 – 10000000

Power factor

0.8000

  • Phase angle36.87 °
  • Real power80.0000 kW
  • Apparent power100.0000 kVA
  • Reactive power60.0000 kvar
  • Correction needed33.7053 kvar
  • Capacitance per phase (delta)223.5150 µF
  • Apparent power after correction84.2105 kVA

Displacement power factor for sinusoidal supplies. Size real capacitor banks with the supplier's data, harmonic study and applicable electrical code.

How this was calculated

PF = P ÷ S = 80 kW ÷ 100 kVA = 0.8.

Phase angle φ = arccos(0.8) = 36.86989765°; reactive power Q = 60 kvar.

Correction Qc = P × (tan φ₁ − tan φ₂) = 80 × (tan 36.86989765° − tan 18.19487234°) = 33.70527159 kvar.

Per-phase capacitance (delta) C = Qc ÷ (3 × 2πf × V²) = 33,705.27159 ÷ (3 × 2π × 50 × 400²) = 223.5150242 µF.

What power factor measures

Power factor is the ratio of real power to apparent power: PF = P ÷ S. It runs from 0 to 1. A PF of 1 means all the current does useful work; lower values mean extra current circulates to supply reactive power, mostly for motor and transformer magnetic fields.

For sinusoidal supplies, PF = cos φ, where φ is the phase angle between voltage and current. A PF of 0.8 corresponds to an angle of 36.9°.

Sizing correction capacitors

Capacitors supply reactive power locally so the supply does not have to. The kvar needed to raise the power factor from PF₁ to PF₂ at a constant real power P is Qc = P × (tan φ₁ − tan φ₂).

Example: an 80 kW load at PF 0.80 has tan φ₁ = 0.75. To reach 0.95, tan φ₂ = 0.329, so Qc = 80 × (0.75 − 0.329) = 33.7 kvar.

Capacitance follows from Q = 2πf × C × V². For a single-phase capacitor, C = Qc ÷ (2πfV²). For a delta-connected three-phase bank, each of the three capacitors carries a third of the kvar at line-to-line voltage.

Limits of this estimate

The calculation assumes sinusoidal voltage and current. Variable-speed drives and other electronic loads add harmonics, which a displacement power factor does not capture and which can overload capacitors. Over-correction to a leading power factor can also raise voltage. Real installations should be designed with the supplier's data and the applicable electrical code.

References

Frequently asked questions

What is a good power factor?

Many utilities charge extra below about 0.9 to 0.95. Check your tariff for the threshold that applies to you.

Can power factor be greater than 1?

No. Real power can never exceed apparent power, so the ratio is at most 1.

Does improving power factor reduce my kWh use?

Mostly no. It reduces current, cable losses and kVA or reactive-power charges, but the load's real energy use in kWh stays about the same.

Last updated . Results are estimates for informational purposes only.