Formula and method
V = IR and P = VI. With power and resistance known, I = √(P/R) and V = √(PR).
Worked example
A 6 Ω resistor carrying 2 A has 12 V across it and dissipates 24 W. Each supported input pair yields the same values.
Solve voltage, current, resistance and power for an ideal resistor from a supported pair of known quantities.
Printed from Calxy · https://www.calxy.net/other/ohms-law-calculator
1e-9 – 1000000000
1e-9 – 1000000000
Voltage
12.0000 V
Positive magnitudes for an ideal resistor in DC or purely resistive RMS AC conditions. It does not model reactive impedance, component ratings or installation safety.
Ohm’s law: V = I × R.
Resistive power: P = V × I = I²R = V²/R.
V = IR and P = VI. With power and resistance known, I = √(P/R) and V = √(PR).
A 6 Ω resistor carrying 2 A has 12 V across it and dissipates 24 W. Each supported input pair yields the same values.
No. It models an ideal resistance. AC circuits with capacitors or inductors require impedance and phase calculations.
Last updated . Results are estimates for informational purposes only.