Ohm’s Law Calculator

Enter any two of voltage, current, resistance and power to solve the other two for an ideal resistor, with the working shown.

Resistance6.0000 Ω
V

1e-9 – 1,000,000,000 V

A

1e-9 – 1,000,000,000 A

Resistance

6.0000 Ω

  • Voltage12.0000 V
  • Current2.0000 A
  • Power dissipated24.0000 W

Positive magnitudes for an ideal resistor in DC or purely resistive RMS AC conditions. It does not model reactive impedance, component ratings or installation safety.

How this was calculated

  1. R = V ÷ IPut in your numbers: R = 12 V ÷ 2 AAnswer: R = 6 Ω
  2. P = V × IPut in your numbers: P = 12 V × 2 AAnswer: P = 24 W
  3. Ohm’s law V = I × R and resistive power P = V × I = I²R = V²/R together link all four quantities.

Formula and method

V = IR and P = VI. With power and resistance known, I = √(P/R) and V = √(PR).

Worked example

A 6 Ω resistor carrying 2 A has 12 V across it and dissipates 24 W. Each supported input pair yields the same values.

Frequently asked questions

Can this calculate reactive AC circuits?

No. It models an ideal resistance. AC circuits with capacitors or inductors require impedance and phase calculations.

References

Last updated . Results are estimates for informational purposes only.