Inverse Trigonometric Functions

arcsin, arccos and arctan undo sine, cosine and tangent on restricted intervals. This sheet gives their domains and ranges, describes their graphs and collects their derivatives, integrals and compositions with the ordinary trig functions.

Definitions, domains and ranges

Sine, cosine and tangent repeat, so they are only invertible on an interval where each value occurs once. y = arcsin x means sin y = x with y in [−π/2, π/2]; y = arccos x means cos y = x with y in [0, π]; y = arctan x means tan y = x with y in (−π/2, π/2). They are also written sin⁻¹ x, cos⁻¹ x and tan⁻¹ x, where ⁻¹ means inverse function, not 1/sin x.

Inverse trig functions
FunctionDomainRange (principal values)Graph
arcsin x[−1, 1][−π/2, π/2]Increasing S-shaped curve from (−1, −π/2) through (0, 0) to (1, π/2); vertical tangents at the ends
arccos x[−1, 1][0, π]Decreasing curve from (−1, π) through (0, π/2) to (1, 0); the arcsin graph reflected and shifted, arccos x = π/2 − arcsin x
arctan xAll real numbers(−π/2, π/2)Increasing curve through (0, 0) with horizontal asymptotes y = −π/2 and y = π/2

Sources: OpenStax: Precalculus 2e §6.3 Inverse Trigonometric Functions; NIST Digital Library of Mathematical Functions: DLMF §4.23 Inverse Trigonometric Functions

Derivatives and integrals

Read in reverse, the derivatives give the standard integrals that produce inverse trig functions: ∫ dx ÷ √(a² − x²) = arcsin(x/a) + C and ∫ dx ÷ (a² + x²) = (1/a)·arctan(x/a) + C for a > 0.

Calculus of the inverse trig functions
FunctionDerivativeIntegral
arcsin x1 ÷ √(1 − x²), |x| < 1x·arcsin x + √(1 − x²) + C
arccos x−1 ÷ √(1 − x²), |x| < 1x·arccos x − √(1 − x²) + C
arctan x1 ÷ (1 + x²)x·arctan x − ½ ln(1 + x²) + C

Sources: OpenStax: Calculus Volume 1 §3.7 Derivatives of Inverse Functions; OpenStax: Calculus Volume 1 §5.7 Integrals Resulting in Inverse Trigonometric Functions; NIST Digital Library of Mathematical Functions: DLMF §4.26 Trigonometric Functions: Integrals

Compositions

Each composition of a trig function with an inverse trig function simplifies to an algebraic expression. Draw a right triangle whose angle θ = arcsin x, arccos x or arctan x, label two sides from x, and find the third side with the Pythagorean theorem.

trig(inverse trig x)
ExpressionSimplifies toValid for
sin(arcsin x)x−1 ≤ x ≤ 1
cos(arcsin x)√(1 − x²)−1 ≤ x ≤ 1
tan(arcsin x)x ÷ √(1 − x²)−1 < x < 1
sin(arccos x)√(1 − x²)−1 ≤ x ≤ 1
cos(arccos x)x−1 ≤ x ≤ 1
tan(arccos x)√(1 − x²) ÷ x−1 ≤ x ≤ 1, x ≠ 0
sin(arctan x)x ÷ √(1 + x²)All real x
cos(arctan x)1 ÷ √(1 + x²)All real x
tan(arctan x)xAll real x
arcsin(sin x)xOnly for −π/2 ≤ x ≤ π/2
arccos(cos x)xOnly for 0 ≤ x ≤ π; in general |x − 2πk|, with k the integer nearest x ÷ 2π
arctan(tan x)xOnly for −π/2 < x < π/2
arccos(sin x)π/2 − xFor −π/2 ≤ x ≤ π/2 (since arccos y = π/2 − arcsin y)
arcsin(cos x)π/2 − xFor 0 ≤ x ≤ π

Sources: OpenStax: Precalculus 2e §6.3 Inverse Trigonometric Functions; NIST Digital Library of Mathematical Functions: DLMF §4.24 Inverse Trigonometric Functions: Further Properties

References

Frequently asked questions

Is sin⁻¹ x the same as 1/sin x?

No. sin⁻¹ x is the inverse function arcsin x, an angle. 1/sin x is the reciprocal, csc x.

Why is arccos(cos x) not always x?

arccos only returns angles between 0 and π. For x outside that interval it returns the angle in [0, π] with the same cosine; for example arccos(cos(3π/2)) = π/2.