Formula and method
aₙ = a₁r^(n − 1). For r ≠ 1, Sₙ = a₁(1 − rⁿ)/(1 − r). For r = 1, Sₙ = na₁.
Worked example
Starting at 2 with ratio 2, the tenth term is 1,024 and the first ten terms sum to 2,046.
Find a geometric sequence’s nth term and finite sum from its starting term, common ratio and term count.
Printed from Calxy · https://www.calxy.net/math/geometric-sequence-calculator
-1000000000 – 1000000000
-1000000000 – 1000000000
1 – 10000
Term 10
1,024.0000
| Index | Term |
|---|---|
| 1 | 2 |
| 2 | 4 |
| 3 | 8 |
| 4 | 16 |
| 5 | 32 |
| 6 | 64 |
| 7 | 128 |
| 8 | 256 |
| 9 | 512 |
| 10 | 1024 |
Term indices start at 1. Very large geometric powers can exceed floating-point range; reduce the term count or ratio if the calculator reports an overflow.
aₙ = a₁r^(n − 1).
Sₙ = a₁(1 − rⁿ)/(1 − r), or n × a₁ when r = 1.
aₙ = a₁r^(n − 1). For r ≠ 1, Sₙ = a₁(1 − rⁿ)/(1 − r). For r = 1, Sₙ = na₁.
Starting at 2 with ratio 2, the tenth term is 1,024 and the first ten terms sum to 2,046.
Every term equals the first term, so the sum is the first term multiplied by the count. The calculator handles this without dividing by zero.
Last updated . Results are estimates for informational purposes only.