Formula and method
aₙ = a₁ + (n − 1)d. The sum is Sₙ = n(a₁ + aₙ)/2, with term numbering starting at one.
Worked example
Starting at 2 with difference 3, the tenth term is 29 and the first ten terms sum to 155.
Find an arithmetic sequence’s nth term, finite sum and first terms from the initial value and common difference.
Printed from Calxy · https://www.calxy.net/math/arithmetic-sequence-calculator
-1000000000 – 1000000000
-1000000000 – 1000000000
1 – 10000
Term 10
29.0000
| Index | Term |
|---|---|
| 1 | 2 |
| 2 | 5 |
| 3 | 8 |
| 4 | 11 |
| 5 | 14 |
| 6 | 17 |
| 7 | 20 |
| 8 | 23 |
| 9 | 26 |
| 10 | 29 |
Term indices start at 1. Very large geometric powers can exceed floating-point range; reduce the term count or ratio if the calculator reports an overflow.
aₙ = a₁ + (n − 1)d.
Sₙ = n(a₁ + aₙ)/2.
aₙ = a₁ + (n − 1)d. The sum is Sₙ = n(a₁ + aₙ)/2, with term numbering starting at one.
Starting at 2 with difference 3, the tenth term is 29 and the first ten terms sum to 155.
Yes. A negative difference creates a decreasing sequence. Term counts must remain positive whole numbers.
Last updated . Results are estimates for informational purposes only.